SOLUTION: I would like all work shown please. 2log(base of 2)1024 = 3x + 1

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Question 647: I would like all work shown please.
2log(base of 2)1024 = 3x + 1
Answer by janinecb(25) About Me  (Show Source):
You can put this solution on YOUR website!
Start by dividing both sides by 2 to get the log by itself.
log(base of 2)1024 = 1/2(3x + 1)
Then you want to think about what log(base of 2)1024 equals. Remember that raising the base of 2 to some exponent equals 1024. 2%5Ey+=+1024
2%5E10+=+1024
So, log(base of 2)1024 actually equals 10.

10 = 1/2(3x + 1) Now multiply both sides by 2.
20 = 3x + 1 Now subtract 1 from both sides.
19 = 3x Now divide both sides by 3.
19/3 = x