SOLUTION: Find the domain y=ln(x^2-19x+78)

Question 646111: Find the domain y=ln(x^2-19x+78)
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
For the function to be defined, the argument of the logarithm must be greater than zero.
The expression can be factored as:
x^2-19x+78 = (x-13)(x-6)
Setting the factored expression = 0 gives x = 6 and x = 13.
We can see that if x is between 6 and 13, one of the factors will always be negative.
So the function's domain is all real numbers less than 6 and greater than 13
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