# SOLUTION: Could you show me how to simplify the expression 2^(x+1)=6^(x-1) using logarithmic principles

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 Question 645972: Could you show me how to simplify the expression 2^(x+1)=6^(x-1) using logarithmic principlesAnswer by ankor@dixie-net.com(15746)   (Show Source): You can put this solution on YOUR website!2^(x+1) = 6^(x-1) : using the log equiv of exponents (x+1)*log(2) = (x-1)*log(6) : Find the logs of 2 and 6; then just basic algebra .301(x+1) = .778(x-1) .301x + .301 = .778x - .778 .301 + .778 = .778x - .301x 1.079 = .477x x = 1.079/.477 x = 2.262 : : You can confirm this on your calc, enter 2^(2.262+1) results: 9.593 enter 6^(2.261-1) results: 9.594 (logs are not exact)