SOLUTION: Working on a logarithm problem but having difficulty. Thanks! Find the value of x for both log41=x log3 x=5 on the log4, the four is just below the log. Hope that is

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Question 64489This question is from textbook college algebra
: Working on a logarithm problem but having difficulty. Thanks!
Find the value of x for both
log41=x
log3 x=5
on the log4, the four is just below the log. Hope that is clear enough.Thanks!This question is from textbook college algebra

Answer by Earlsdon(6103) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
1) log4%281%29+=+x The base is 4. Rewrite this in exponential form.
4%5Ex+=+1 Now take the log (base 10) of both sides.
xlog%284%29+=+log%28%281%29%29 Divide both sides by log(4).
x+=+%28log%281%29%29%2Flog%284%29 But log(1) = 0:
x+=+0
2) log3%28x%29+=+5 The base is 3. Rewrite in exponential form.
3%5E5+=+x
x+=+243