SOLUTION: Solve. log(base4)(x+4)-log(base16)x=1

Question 644599: Solve. log(base4)(x+4)-log(base16)x=1
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve. log(base4)(x+4)-log(base16)x=1
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log4(x+4) - log(x)/log(16) = 1
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log4(x+4) - log4(x)/log4(16) = 1
----
log4(x+4) - (1/4)log4(x) = 1
----
(3/4)log4(x) = 1
log4(x) = 4/3
---
x = 4^(4/3)
----
x = 6.35
===========================
Cheers,
Stan H.
===========================
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!

Solve. log(base4)(x+4)-log(base16)x=1

----- Applying change of base to base 4

----- Multiplying by LCD, 2

----- Cross-multiplying

(x � 4)(x � 4) = 0

======
Check
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1.5 - .5 = 1
1 = 1 (TRUE)

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