SOLUTION: My question is this... Log(base of 2)(4x)= 5-Log(base of 2)(x-2)

Question 63784: My question is this...
Log(base of 2)(4x)= 5-Log(base of 2)(x-2)
Answer by tanimachatterjee(60) (Show Source): You can put this solution on YOUR website!
Log(base of 2)(4x)= 5-Log(base of 2)(x-2)
or Log(base of 2)(4x) + Log(base of 2)(x-2) = 5
or Log(base of 2)(4x)(x-2)=Log(base of 2)(2^5)[we know Loga + logb=logab base r same]
or 4x(x-2)= 2^5=32
or x^2 -2x = 32/4 =8[factorize the equn]
or x^2 -2x -8 =0
or x^2 -4x +2x -8 =0
or x(x-4) +2(x-4) =0
or (x-4)(x+2)=0
then either (x-4) =0
ie x=4
or x+2 =0
x=-2

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