SOLUTION: Solve for x: log(4x + 8) - log 2=1 Im baffled.I have no idea what the second part means or even how to begin.

Question 63580: Solve for x: log(4x + 8) - log 2=1
Im baffled.I have no idea what the second part means or even how to begin.
Answer by praseenakos@yahoo.com(507) (Show Source): You can put this solution on YOUR website!
QUESTION:
Solve for x: log(4x + 8) - log 2=1

ANSWER:

Use law of logarithm,

log A - logB = log(a/B)

Also here we can take,
1= log 10, because, value of log 10 to the base10 is 1

so, log(4x + 8) - log 2=1

==> log(4x + 8) - log 2=log 10

==> log{(4x + 8)/2 }= log 10

Both side we have logarithm, so,

==> 4x + 8)/2 = 10

==> 4x + 8 = 10 * 2

==> 4x + 8 = 20

==> 4x = 20 - 8

==> 4x = 12

==> x = 12/4

==> x = 3

Hope you understood.

Regards,
praseenakos@yahoo.co.in

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