SOLUTION: Write as a single logarithm: log 12 + log (x-2) - log 2. I thought that I might have to turn it into exponetial form first but Im not sure.

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Question 63579: Write as a single logarithm: log 12 + log (x-2) - log 2.
I thought that I might have to turn it into exponetial form first but Im not sure.

Answer by praseenakos@yahoo.com(507)   (Show Source): You can put this solution on YOUR website!
ANSWER:

Write as a single logarithm: log 12 + log (x-2) - log 2.
I thought that I might have to turn it into exponetial form first but Im not sure.
ANSWER:


LAWS OF LOGARITHM:


logA + logB = log AB
log A - log B = log (A/B)




So, log 12 + log (x-2) = log {12 * (x-2)}
= log {12(x-2)}


so, log 12 + log (x-2) - log 2 = log {12(x-2)} - log 2

= log {12(x-2)/2}

= log {6(x-2)}

= log {6x- 12}


Hope you understood.

Regards,
praseenakos@yahoo.co.in






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