SOLUTION: Hello. I got these questions and I really could use some help. 1. 6e^(1-x)+1 = 21 2. 4x + 2e^(2y) -8 = 0. Withe the first one, I got as far as the fraction: lne^(1-x) = ln

Question 634412: Hello. I got these questions and I really could use some help.
1. 6e^(1-x)+1 = 21
2. 4x + 2e^(2y) -8 = 0.

Withe the first one, I got as far as the fraction:
lne^(1-x) = ln 20/6
Please help.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
1. 6e^(1-x)+1 = 21
e^(1-x) = 20/6 = 10/3
-----
ln(e^xyz) = xyz
-----
1-x = ln(10/3)
x = 1 - ln(10/3)
x =~ -0.2039728
===================
2. 4x + 2e^(2y) -8 = 0
What do you want to do with this one?

RELATED QUESTIONS
Hello Tutor, I am in need of some help if you can help me out I would appreciate it. (answered by edjones)

Can you please tell me if i got these correct? Im doing a practice test to study for my... (answered by Edwin McCravy,solver91311)

I have two Questions on inequalities: Solve: -x+1< -1/2 and |b+2|< -1 I could... (answered by mukhopadhyay)

log4(x^2)-log4(4x-4)=0 I could really use some help solving this... (answered by lwsshak3)

Hello, I am stuck on a problem for homework and need some help. I worked it out but am... (answered by Alan3354)

Could someone tell me if I got these problems right? The first two are the Substitution... (answered by jim_thompson5910)

I really need help. If you could please answer these two questions for me I would be... (answered by MathLover1)

If anyone could help me out with these graphing questions, I would REALLY appreciate it!... (answered by jim_thompson5910)

Hello out there,I really need some help with some tough problems,the first one is Solve... (answered by cheesey)