SOLUTION: I need help solving for x algebraically.
(log base 3(x-4)) = (log base 3 (x-2)) =1
I am so lost. I thought I could cancel out logs ad get
x^2 -2x -4x -8 = 3^1
x^2 -6x -1
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-> SOLUTION: I need help solving for x algebraically.
(log base 3(x-4)) = (log base 3 (x-2)) =1
I am so lost. I thought I could cancel out logs ad get
x^2 -2x -4x -8 = 3^1
x^2 -6x -1
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Question 634207: I need help solving for x algebraically.
(log base 3(x-4)) = (log base 3 (x-2)) =1
I am so lost. I thought I could cancel out logs ad get
x^2 -2x -4x -8 = 3^1
x^2 -6x -11 =0
hm.... help? Answer by Alan3354(69443) (Show Source):