SOLUTION: 5^2x+4*5^x-5=0
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Question 633311: 5^2x+4*5^x-5=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
5^2x+4*5^x-5=0
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(5^x)^2 + 4(5^x) - 5 = 0
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Factor:
[(5^x)+5] = 0
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5^x = -5 or 5^x = 1
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Note: 5^x cannot be -5
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Solve: 5^x = 1
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x = 0
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Cheers,
Stan H.
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