SOLUTION: if logb3=0.23 and logb8=0.71 find logb24.
Algebra.Com
Question 627155: if logb3=0.23 and logb8=0.71 find logb24.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Hint: The sum of the logs is the log of the product. That is:
 + \log_b(y) = \log_b(xy))
John
My calculator said it, I believe it, that settles it
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