# SOLUTION: I need some help with log please Solve ln(3+3x)-ln(x-4)=ln5 thanks for your time

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 Click here to see ALL problems on logarithm Question 62435: I need some help with log please Solve ln(3+3x)-ln(x-4)=ln5 thanks for your timeAnswer by uma(370)   (Show Source): You can put this solution on YOUR website!ln(3+3x) - ln(x-4) = ln5 ==> ln[(3+3x)/(x-4)] = ln 5 [because lna - ln b = ln(a/b)] Removing ln from either side we get.... [(3+3x)/(x-4)] = 5 Multiplying by (x-4) on either side we get.. 3 + 3x = 5(x-4) ==> 3 + 3x = 5x - 20 ==> 3 + 3x - 5x = 5x - 20 - 5x ==> 3 - 2x = - 20 ==> 3 - 2x - 3 = - 20 - 3 ==> -2x = - 23 ==> -2x/-2 = -23/-2 ==> x = 23/2 ==> x = 11.5 Good Luck!!!