Question 624311: log(1-2x)-2logx = 1-log(2-5x) Found 2 solutions by oscargut, ewatrrr:Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website! log(1-2x)-2logx = 1-log(2-5x)
log(1-2x)-log(x^2) = log(10)-log(2-5x)
log((1-2x)/x^2) = log(10/(2-5x))
(1-2x)/x^2 = 10/(2-5x)
(1-2x)(2-5x)=10x^2
10x^2-9x+2 = 10x^2
-9x+2 = 0
x = 2/9
Answer: x = 2/9