SOLUTION: What is the value of x in the equation ln (x + 6) � ln (2x � 1) = 1?

Question 623432: What is the value of x in the equation ln (x + 6) � ln (2x � 1) = 1?
Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
ln(x + 6) � ln(2x � 1) = 1

ln[(x + 6)/(2x � 1)] = 1

(x + 6)/(2x � 1) = e^1

(x + 6)/(2x � 1) = e

x + 6 = e(2x � 1)

x + 6 = 2ex � e

x - 2ex = � e - 6

x(1 - 2e) = � e - 6

x = (�e - 6)/(1 - 2e)

So the solution is
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
What is the value of x in the equation ln (x + 6) � ln (2x � 1) = 1?
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ln (x + 6) � ln (2x � 1) = 1
ln ((x + 6)/(2x � 1)) = 1
(x + 6)/(2x � 1) = e
x + 6 = e*(2x � 1) = e*2x - e
x - 2e*x = -e - 6
x*(2e - 1) = e + 6
x = (e+6)/(2e-1)
x =~ 1.96509788

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