You can
put this solution on YOUR website!(1/3)log
2(x+6) = log
83x
=> (1/3)log
2(x+6) = (log
23x)/(log
28)
=> (1/3)log
2(x+6) = (log
23x)/3*(log
22)
=> (1/3)log
2(x+6) = (1/3)(log
23x)
=> log
2(x+6) = (log
23x)
Taking antilog on both sides
=> (x+6) = 3x
=> 2x = 6
=> x = 3