SOLUTION: Solve the logarithmic equation: log(x+1)+log(x-1)=log3

Algebra.Com
Question 619317: Solve the logarithmic equation: log(x+1)+log(x-1)=log3
Answer by sophxmai(62)   (Show Source): You can put this solution on YOUR website!
Using the rule loga+logb=logab

log(x+1)+log(x-1)=log3
log[(x+1)*(x-1)]=log3
log(x^2-x+x-1)=log3
log(x^2-1)=log3
10^[log(x^2-1)]=10^log3
x^2-1=3
x^2=4
x=sqrt4
x=+2,-2

RELATED QUESTIONS

Solve the logarithmic equation log x + log (x-3)=... (answered by Edwin McCravy)
Solve the logarithmic equation x=log3 1/81 I've tried x=3log 1/81... (answered by Cromlix)
log x-log3=1 (answered by stanbon)
log4x=log5+log(x-1) solve the logarithmic... (answered by stanbon)
Solve the following logarithmic equation:... (answered by lwsshak3)
Solve the Logarithmic equation log₆x = 1 - log₆(x-5) Thanks!!! (answered by Fombitz)
Solve the following logarithmic equation. log(2x+8)=1+ log(x-5) Thanks so... (answered by nerdybill)
solve the following logarithmic equation log(3x+7)=1+log(x-6) can someone please... (answered by Fombitz)
Solve the logarithmic equation: Log base 4(2x+1)= Log base 4(x-3) + Log base... (answered by solver91311)