SOLUTION: What is log(base3)8+log(base3)(7-2x)=2

SOLUTION: What is log(base3)8+log(base3)(7-2x)=2

Algebra.Com

Question 618297: What is log(base3)8+log(base3)(7-2x)=2
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
log(base3)8+log(base3)(7-2x)=2
.

RELATED QUESTIONS
What is... (answered by lwsshak3)

{{{log... (answered by edjones)

Use properties of logarithms to solve the equation log(base3)y � log(base3)7 =... (answered by nerdybill)

log(base5)2=log(base3)m-log(base3)n (answered by Theo)

what is the log base3 of... (answered by lwsshak3)

2+log base3 ^(2x+5)- log base3^x = 4 , I can not figure out how to work it out properly.... (answered by jsmallt9)

log(base3)(2x-1)=3 (answered by nerdybill)

1/2 log base3 X= 2 log base3 2 (answered by edjones)

log(Base3)(x-1)... (answered by rapaljer)