SOLUTION: What is log(base3)8+log(base3)(7-2x)=2
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Question 618296: What is log(base3)8+log(base3)(7-2x)=2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
What is log(base3)8+log(base3)(7-2x)=2
log3(8)+log3(7-2x)=2
place under single log
log3[8*(7-2x)]=2
convert to exponential form:
3^2=8(7-2x)
9=56-16x
16x=47
x=47/16
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