Let both sides have a base of 10.
Remember that log is assumed to be 10 if there's no number specified. Because we made the equation have a base of 10, we can then cancel out the logs.
Multiply x by each term inside the parentheses.
Square 10.
Move 100 to the other side.
Factor.
Solved by pluggable solver: Factoring Quadratics with a leading coefficient of 1 (a=1) | |||||||||||||||||||||||||||||||||||||||||||||||||||||||
In order to factor Factors: 1,2,4,5,10,20,25,50,100, -1,-2,-4,-5,-10,-20,-25,-50,-100,List the negative factors as well. This will allow us to find all possible combinations These factors pair up to multiply to -100. (-1)*(100)=-100 (-2)*(50)=-100 (-4)*(25)=-100 (-5)*(20)=-100 (-10)*(10)=-100 Now which of these pairs add to 21? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 21
Set each of the factors equal to 0. Simplify. Here is the final answer: :)
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