SOLUTION: Please help me solve this equation: use the laws of logarithms to solve this equation.
ln(3-x)=ln(3x-x^2)
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Question 611962: Please help me solve this equation: use the laws of logarithms to solve this equation.
ln(3-x)=ln(3x-x^2)
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
ln(3-x)=ln(3x-x^2)
3-x = 3x-x^2
-x+3 = 3x-x^2
x^2-x+3 = 3x
x^2-4x+3 = 0
(x-1)(x-3) = 0
x = {1,3}
since you can't take ln(0), we determine that x=3 is an extraneous solution -- throw it out leaving:
x = 1
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