SOLUTION: solve 3log 6 base 4 - log 8 base 4 = log x base 4
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Question 611672: solve 3log 6 base 4 - log 8 base 4 = log x base 4
Found 2 solutions by stanbon, solver91311:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3log 6 base 4 - log 8 base 4 = log x base 4
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log4(6^3) - log4(8) = log4(x)
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log4[216/8] = log4(x)
log4[27] = log4(x)
----
x = 27
====================
Cheers,
Stan H.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ -\ \log_4(8)\ =\ \log_4(x))
Use:
\ =\ n\log_b(x))
to write:
\ -\ \log_4(8)\ =\ \log_4(x))
Use: "The difference of the logs is the log of the quotient" to write:
\ =\ \log_4(x))
Use:
\ =\ \log_b(y)\ \ \Leftrightarrow\ \ x\ =\ y)
To write:
Just do the arithmetic. Hint 
and 36 is divisible by 4 while 6 is divisible by 2, 4 and 2 being the factors of the denominator.
John
My calculator said it, I believe it, that settles it
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