SOLUTION: ( 1+ log base n of m) log base nm of x = log base n of x. How????

Algebra.Com
Question 609117: ( 1+ log base n of m) log base nm of x = log base n of x. How????
Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
( 1+ log base n of m) log base nm of x = log base n of x.
1+logn(m)*lognm(x)
convert to base n
1+logn(m)*log(x)/logn(nm)
=1+logn(m)*logn(x)/logn(n)+logn(m)
log(n)=1(log of base=1)
=1+logn(m)*logn(x)/1+logn(m)
=logn(x)

RELATED QUESTIONS

1/2 log (base 3) of M + 3 log (base a) of N = 1 , express M in terms of N? (answered by lwsshak3)
how do you solve log base 4 (log base 3 (log base 2 of X)) = 0?? (answered by stanbon)
1/2 log(base3)of M+ 3 log (base a ) of N=1 , express M in terms of... (answered by mccravyedwin)
Log base 8 of... (answered by josmiceli)
Find the exact value of (log base 2 of 3)(log base 3 of 4)(log base 4 of 5)...(log base n (answered by Fombitz)
Given that log base 3 of 6 = m and log base 6 of 5 =n, express log base 3 of 10 in terms... (answered by richard1234)
Log base 3 of x=log base 9 of 81 (answered by ewatrrr)
solve for X: log (log base e of... (answered by JimboP1977)
log base 2 (log base 3 (log base 5 of x)) = 0 (answered by stanbon)