SOLUTION: I am trying to figure out how to find x in: -4log base 2 (-2x)=-8 I know that it can be re-written as: log base 2 (-2x^-4)=-8 I think the next step would be to do: log base 2

Algebra.Com
Question 609063: I am trying to figure out how to find x in: -4log base 2 (-2x)=-8
I know that it can be re-written as: log base 2 (-2x^-4)=-8
I think the next step would be to do: log base 2 (-2) + log base 2 (x^-4) = -8
Is this right? How would I go about finding x?
Thank you!!
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi



    ||Dividing both sides by -4

       2^2 = -2x

        -2 = x

 Rules Governing Logarithms                                    

 ******











 

RELATED QUESTIONS


LOGx + LOG(x-15) = 2    Solve for x. Answer is 20 but I can not figure out how to get it.  (answered by ankor@dixie-net.com)

Thank you for helping me with the solution to the following problem.  Our solutions do... (answered by funmath,josmiceli)

How to graph polynomials. Where do I start? I am lost on these two problems. I don't know  (answered by stanbon)

Simplify or solve for x.

log base pi of e = x^2

I have the problem written out to... (answered by jim_thompson5910)

7 ^n=12
8^n+1=3
log 3x=2
4log x=4

I can't figure how to solve... (answered by Alan3354)

Evaluate the log expression: {{{8^((log((base8))20))}}}

So I know that log(base... (answered by josgarithmetic,MathLover1,MathTherapy)

I am trying to figure out how to simplify and hence solve the following equation.... (answered by khwang)

Solve for x.

log base 6 of (3x+14) - log base 6 of 5 = log base 6 of (2x)


(I have  (answered by lwsshak3)

Check work, rewrite the expression below as a single logarithm?
I have to rewrite this... (answered by josmiceli)