SOLUTION: x^log2(base) x +32x^log2(base)x=18

Algebra.Com
Question 607977: x^log2(base) x +32x^log2(base)x=18
Answer by lynnlo(4176)   (Show Source): You can put this solution on YOUR website!
33x log2x=18
RELATED QUESTIONS

2+log2 x=log2 (3+X^2) "2" is the base (answered by josgarithmetic)
log2(x)+log2(x+1)=log2(6) (answered by LinnW)
Log2 (x+2) = log2 3-log2... (answered by Alan3354,MathTherapy)
Log2 (x+1) - Log2 X= Log2... (answered by htmentor)
Log2 (x+1) - Log2 X= Log2 4 (answered by Gentle Phill)
How would I solve this? log2(x-3)-log2(2x+1)=log24 (log base 2,... (answered by jsmallt9)
log2 (base of 2) of x + 5 (no parentheses) = 8 - log2 (base of 2) of... (answered by stanbon)
log2^x+log2^4=3 (answered by edjones)
log2^x = log2^5... (answered by themathtutor2009)