SOLUTION: log(baseb) (radical a/c)
Log(b)(sqrt a/ c)
log(baseb)a=10
log(baseb)c=4
Algebra.Com
Question 606679: log(baseb) (radical a/c)
Log(b)(sqrt a/ c)
log(baseb)a=10
log(baseb)c=4
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
I'm not sure whether you mean
)
or
)
Either way, proceed as follows:
Recall that the log of the quotient is the difference of the logs, so you either have:
\ -\ \log_b\left(\sqrt{c}\right))
or
\ -\ \log_b\left(c\right))
Then recall that 
and that \ =\ n\,\cdot\,\log\left(\alpha\right))
So you either have:
\ -\ \frac{1}{2}\,\cdot\,\log_b\left(c\right))
or
\ -\ \log_b\left(c\right))
Substituting, you either have
or
John
My calculator said it, I believe it, that settles it
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