SOLUTION: The population in Cleveland (in thousands) can be modeled by the equation
P(t)=22e^0.014(t)
What is the doubling time of Cleveland's population to the nearest month?
I und
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Question 606667: The population in Cleveland (in thousands) can be modeled by the equation
P(t)=22e^0.014(t)
What is the doubling time of Cleveland's population to the nearest month?
I understand how to do these when you have a population number, but this question doesn't. Help please!
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
The population in Cleveland (in thousands) can be modeled by the equation
P(t)=22e^0.014(t)
What is the doubling time of Cleveland's population to the nearest month?
**
The formula I think is: P=Poe^kt, Po=initial population, k=growth rate, P=population after t years
For given problem:
k=.014
P/Po=2
e^.014t=2
take log of both sides
.014t*lne=ln2
t=ln2/.014≈49.51 yrs
ans:
Doubling time of Cleveland's population:appproximately 594 months
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