SOLUTION: how do you solve:
log base 3 (x+4)+log base 3 (x-2)=3
Algebra.Com
Question 605068: how do you solve:
log base 3 (x+4)+log base 3 (x-2)=3
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
log base 3 (x+4)+log base 3 (x-2) = 3
Combine the logs
FOIL
the exponent equiv of logs
:
;
:
Factors to
(x+7)(x-5) = 0
Two solutions
x = -7
x = 5, since we are dealing with logs, only the positive solution is valid
RELATED QUESTIONS
how do you solve log base 4 (log base 3 (log base 2 of X)) = 0??
(answered by stanbon)
how do i solve (log base 4 (x+3))+(log base 4... (answered by stanbon,solver91311)
how do you solve log base 4 of (x+3)+log base 4 of... (answered by lwsshak3)
How do I solve log base 4(x+5)=3+log base... (answered by stanbon,MathTherapy)
how do i solve log base 3 (x-8)+ log base 3 x... (answered by ewatrrr)
How do you solve this equation?
Log base 3 x+ Log base 3... (answered by ankor@dixie-net.com)
solve:
log 4 base 2 - log (x+3) base 2 = log 8 base... (answered by lwsshak3)
How do you solve
Log (3x) base 5 + log(x-3) base 5= log 30 base 5 (answered by josmiceli)
Solve for x:
(A.) (5/2) log(base 4)4 = log(base 4)(2x-3)
(B.) Log(base 3)(x+2)-... (answered by stanbon)