# SOLUTION: Find the values given that log base a 16=2.846 and log base a 3=0.573: log base a 144a Please help me I do not understand how to find the value. Thank you!

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Find the values given that log base a 16=2.846 and log base a 3=0.573: log base a 144a Please help me I do not understand how to find the value. Thank you!      Log On

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 Click here to see ALL problems on logarithm Question 602473: Find the values given that log base a 16=2.846 and log base a 3=0.573: log base a 144a Please help me I do not understand how to find the value. Thank you!Answer by jim_thompson5910(28504)   (Show Source): You can put this solution on YOUR website!Note: All logs shown below are in base 'a' log(144) log(16*9) log(16)+log(9) log(16)+log(3^2) log(16)+2*log(3) 2.846+2*0.573 2.846+1.146 3.992 Answer: So $\Large \log_{a}(144) = {\color{red} 3.992} \ \text{where } \log_{a}(16)=2.846 \ \text{ and } \log_{a}(3)=0.573$