SOLUTION: Find the values given that log base a 16=2.846 and log base a 3=0.573: log base a 144a Please help me I do not understand how to find the value. Thank you!

Question 602473: Find the values given that log base a 16=2.846 and log base a 3=0.573:
log base a 144a
Please help me I do not understand how to find the value. Thank you!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Note: All logs shown below are in base 'a'

log(144)

log(16*9)

log(16)+log(9)

log(16)+log(3^2)

log(16)+2*log(3)

2.846+2*0.573

2.846+1.146

3.992

Answer: So $\log_{a}(144) = {\color{red} 3.992} \ \text{where } \log_{a}(16)=2.846 \ \text{ and } \log_{a}(3)=0.573$
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