SOLUTION: condensing logarithms
4log(base)6 4+1/7log(base)6(r-8)-1/2log(base)6r
Algebra.Com
Question 602365: condensing logarithms
4log(base)6 4+1/7log(base)6(r-8)-1/2log(base)6r
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
condensing logarithms
4log(base)6 4+1/7log(base)6(r-8)-1/2log(base)6r
=4log6(4)+1/7log6(r-8)-1/2log6(r)
=log6[(4^4)*(r-8)^(1/7)/r^(1/2)]
=log6[256*(r-8)^(1/7)/r^(1/2)]
RELATED QUESTIONS
3log(base 5)X=4log(base 5)2-1/2log(base... (answered by stanbon)
4log base 2 5+4log base 2 6-2log base 2... (answered by MathLover1)
How do you solve 2log[base 6](x)-2log[base 6] (x-4)= 1 (answered by stanbon)
Question: 3(log(base 6)(x)+2log(base 6)(y)-4log(base 6)(z))
Answer: 3log(base... (answered by ewatrrr)
1 (base 6) + 5 (base 6)
4 (base 6) + 14 (base 6)
6543 (base 8) + 7426 (base... (answered by stanbon)
2log(base... (answered by Fombitz)
2log base 2 (x-6)- log base... (answered by Boreal)
Please help me solve this.
2log (27/8) base x =6
and
1/3log x base 10... (answered by Theo)
2log base 10 6 - 1/3log base 10 27 = log base 10 of x
need help... (answered by lwsshak3)