SOLUTION: How do I solve 12e^(4x-3)=72
Algebra.Com
Question 602054: How do I solve 12e^(4x-3)=72
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
How do I solve
12e^(4x-3)=72
e^(4x-3)=72/12=6
take log of both sides
(4x-3)lne=ln6
lne=1 (log of base=1)
4x-3=ln6
4x=ln6+3
x=(ln6+3)/4
x≈1.1979
RELATED QUESTIONS
12e^2x=5^x I need to solve for x and i dont know how... (answered by jsmallt9)
how do i solve... (answered by Gogonati,Alan3354)
Solve the equation if possible.
12e^8t-e=8e^8t
I don't really know how to go about... (answered by Alan3354,Edwin McCravy,solver91311)
Must all be rounded to four decimal places
9e^19x = 16 ---> 0.0303
5(1+10^2x) = 8 (answered by Edwin McCravy)
How do i solve this equation?... (answered by Alwayscheerful)
how do i solve... (answered by Fombitz)
How do I solve this equation:
x - 0.25x =... (answered by rfer)
how do I solve this one?
-1/4x=3/4
(answered by xcentaur)
y=3/4x+2...How do I solve this? (answered by chitra)