SOLUTION: I need a lot of help on.... log base 4 (x+1) - log base 4x=3
Algebra.Com
Question 600332: I need a lot of help on.... log base 4 (x+1) - log base 4x=3
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation
Condense the logs using the identity
Convert to exponential form.
Cube 4 to get 64
Multiply both sides by x
Subtract x from both sides
Combine like terms
Divide both sides by 63 to isolate x
Flip the equation.
So the solution is
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log base 4 (x+1) - log base 4x=3
------
log4(x+1) - log4(x) = 3
----
log4[(x+1)/x] = 3
----
(x+1)/x = 4^3
-----
(x+1)/x = 64
---
x+1 = 64x
63x = 1
x = 1/63
===============
Cheers,
Stan H.
RELATED QUESTIONS
i need help in solving log(base 3)x+log(base 3)(2x)-log(base... (answered by Alan3354)
I need help solving:
2 log (x+1) base 4 = log (11-x) base... (answered by solver91311)
Need help solving log base 2(5x+4) - log base... (answered by lwsshak3)
log base(1/4)8-log base(5)0.2+log base(square root of a)a..........
Please help me to... (answered by josmiceli)
I need help with:
1) log (x² - 1) = log 3
2) log base 2 (x + 3) + log base 2 (x - 3)... (answered by savvyhush23)
Solve for x:
A.) Log(base 3)4 + log(base 3)5 = log(base 3)(4x+5)
B.)log(base 7)6... (answered by algebrapro18)
I need help with the following problems:
1. 2log base 8 4- 1 over three log base 8 8... (answered by ewatrrr)
I would like help on these questions:
log base 0.25 of sqrt2 - log base sqrt2 of 0.25
(answered by jsmallt9)
Solve for x:
(A.) Log(base 5)7 + log(base 5)8 = log(base 5)(2x-4)
(B.) Log(base 3)... (answered by Nate)