SOLUTION: what is the way to solve the logarithms a.) 2e^9x=4 b.)ln(4x − 3) = 4 and c.)
7^x + 1 = 4? I keep getting a negative answer fot c. and I know it is not supposed to be that
Algebra.Com
Question 599931: what is the way to solve the logarithms a.) 2e^9x=4 b.)ln(4x − 3) = 4 and c.)
7^x + 1 = 4? I keep getting a negative answer fot c. and I know it is not supposed to be that way. I am getting depressed. Can you please help? ex.:
7^x+1=4, log7^x+1=4, (x+1)log7=log4, xlog7+log7=log4-log7, x=log4-log7/log7. All my answers are negatives, and are wrong.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
a.) 2e^9x=4
e^9x=4/2=2
take log of both sides
9xlne=ln2
lne=1
9x=ln2
x=ln2/9
x≈0.077
..
b.)ln(4x − 3) = 4
convert to exponential form: base(e) raised to log of number(4)=number(4x-3)
e^4=4x-3
4x=e^4+3
x=(e^4+3)/4
x≈14.4
..
c.)7^x + 1 = 4
7^x=3
xlog7=log3
x=log3/log7
x≈0.564
RELATED QUESTIONS
Hello,
I have a problem with the following exponential equation, each time I try to... (answered by RAY100)
7) The correct solution to 3=2√x+x is:
a. x=1 and x=3
b. x=1 and x= 4
c.... (answered by longjonsilver)
Given the parent functions f(x) = log3 (5x − 5) and g(x) = log3 (x − 1), what (answered by ewatrrr)
1. Find all roots of x3 + 2x2 + 2x + 1. Hint: Find the rational one(s) first.
A.... (answered by Alan3354)
Contract the expressions. That is, use the properties of logarithms to write each... (answered by stanbon)
Contract the expressions. That is, use the properties of logarithms to write each... (answered by lwsshak3)
Solve the equation (f compose g)(x) = 0. (Enter your answers as a comma-separated list.)
(answered by stanbon)
Solve the logarithmic or exponential equation.
1.(525)/(1+e^-x)=275
2.ln(x +1) − (answered by solver91311)
4e^x+2=32
ln(5x-3)^1/3=2
2x^(3x-2)+4=16
2e^(x-2)=e^x+7
1/3lnx+ln2-ln3=3... (answered by ankor@dixie-net.com)