SOLUTION: log5(2x^2-5x+2)-log5(2x-1)+log5 25=3

Question 597486: log5(2x^2-5x+2)-log5(2x-1)+log5 25=3
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
log5(2x^2-5x+2)-log5(2x-1)+log5 25=3
place under single log
log5[(2x^2-5x+2)(25)/(2x-1)]=3
convert to exponential form:
5^3=[(2x^2-5x+2)(25)/(2x-1)]=125
(2x-1)(x-2)(25)/(2x-1)=125
(x-2)(25)=125
x-2=5
x=7
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