SOLUTION: determine Log 6a base a. If Log 6 base a =.7782 and log2 base a =.3869
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Question 597141: determine Log 6a base a. If Log 6 base a =.7782 and log2 base a =.3869
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Use "The log of the product is the sum of the logs," i.e.
 + \log_b(y) = \log_b(xy))
to write
\ =\ \log_a(6)\ +\ \log_a(a))
Use
\ =\ 1\ \forall\ b\ >\ 0\ \in\ \mathbb{R})
to write
\ =\ \log_a(6)\ +\ 1)
Use the given fact \ =\ .7782)
to write
\ =\ 1.7782)
John
My calculator said it, I believe it, that settles it
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