SOLUTION: find the solution of 2log3x-3log3y=7 and log3x-2log3y=4

Question 596777: find the solution of 2log3x-3log3y=7 and log3x-2log3y=4
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
find the solution of
1) 2log3x-3log3y=7
2) log3x-2log3y=4
multiply eq2 by 2
3) 2log3x-4log3y=8
1) 2log3x-3log3y=7
subtract eq1 fm eq3
-log3y=1
log3y=-1
y=3^-1 (exponential form)
y=1/3
..
multiply eq1 by 2 and eq2 by 3
4log3x-6log3y=14
3log3x-6log3y=12
subtract
log3x=2
x=3^2 (exponential form)
x=9

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