SOLUTION: Solve:
log(base 2) x + log(base 6) x =3
Please show steps. thanks
Algebra.Com
Question 594684: Solve:
log(base 2) x + log(base 6) x =3
Please show steps. thanks
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve:
log(base 2) x + log(base 6) x =3
Please show steps.
**
convert to log(base 2)
log2(x)+log2(x)/log2(6)=3
place under single log
log2[(x^2/log2(6)]=3
convert to exponential form:
2^3=x^2/log2(6)=8
x^2=8*log2(6)
using calculator:
x=√(8*log2(6))≈20.68
x≈4.55
RELATED QUESTIONS
1. Solve the following equations
a) log(base 5)x+2 + log(base 5) x-2 - log(base 5)4 =... (answered by mananth)
Solve and check
a)2logm + 3logm = 10
b)log(base 3)x^2 - log(base 3)2x = 2
c)log(base... (answered by solver91311)
Please solve I'm so lost!
Log (base 2) x+3=log (base 2) x-3 + log (base 6) 36... (answered by Alan3354)
1. Solve the following equations
a) log(base 2) x+1 + log(base 2) x-1 = 3
b) log(base... (answered by lwsshak3)
If log(base 3)2 = x simplify each logarithm
a) log(base 3)8
b) log(base 3)24
c)... (answered by josmiceli)
1. Solve the following equations
a) log(base 2)x+1 - log(base 2) 2 = log(base 2)5... (answered by lynnlo)
{{{ log(base 2) (6x+4)=6 }}}. Please show me how to solve for x.... (answered by lwsshak3)
log base 3 (x+2)+log base 3 of 6=3
Solve for x...
I need the listed steps please... (answered by josgarithmetic)
please help solve this logartihm:
log(base 2)x+log(base 2)(x-2)-log(base... (answered by Alan3354)