SOLUTION: log base 4 of 3x = log base 32 of 7x whats x???

Question 591513: log base 4 of 3x = log base 32 of 7x

whats x???
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log base 4 of 3x = log base 32 of 7x
-----
log4(3x) = log32(7x)
-----
= log(3x)/log(4) = log(7x)/log(32)
------
Let the base be 2:
-------
= log2(3x)/2 = log2(7x)/5
----
= log(3x) = (2/5)log(7x)
----
= log(3) + log(x) = (2/5)log(7) + (2/5)log(x)
----
= (3/5)log(x) = (2/5)log(7)- log(3)
----
log(x^(3/5)) = log[7^(2/5)/3]
----
x^(3/5) = 7^(2/5) / 3
-----
x^(3/5) = 0.7260
x = 0.7260^(5/3)
x = 0.5864
=================
Cheers,
Stan H.
=================
RELATED QUESTIONS
solve for x: log base 3 (7x+4)-log base 3 of 2 = 2logbase3 of... (answered by stanbon,josmiceli)

log base 2 of... (answered by jim_thompson5910)

Log base 32 of (x)=... (answered by ewatrrr)

log base b of (x+2) - log base b of 4 is equal to log base b of 3x (answered by MathLover1,Alan3354)

how do you solve log base 4 (log base 3 (log base 2 of X)) = 0?? (answered by stanbon)

log base 2 (3x+2) -log base 4... (answered by stanbon)

log base 4 of 5 + log base 4 of x = log 4 of... (answered by stanbon,DrBeeee)

Solve for x: log base 4 of(x^2+3x) - log base 4... (answered by stanbon)

find x log base 2 (log base 3 (log 4 of... (answered by greenestamps)