SOLUTION: log base 4 time 64x .......... simplify the expresion solve it

Question 590835: log base 4 time 64x .......... simplify the expresion solve it
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
$\log_{4}(64x)$

$\log_{4}(64)+\log_{4}(x)$

$\log_{4}(4^3)+\log_{4}(x)$

$3\log_{4}(4)+\log_{4}(x)$

$3(1)+\log_{4}(x)$

$3+\log_{4}(x)$

$\text{So } \ \log_{4}(64x) = 3+\log_{4}(x) \ \ \text{for all domain values of x.}$
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