SOLUTION: log(7)36-log(7)2x=log(7)4

Algebra.Com
Question 588567: log(7)36-log(7)2x=log(7)4
Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
log(7)36-log(7)2x=log(7)4
log7(36)-log7(2x)-log7(4)=0
log7(36)-(log7(2x)+log7(4))=0
log7[36/2x*4]=0
convert to exponential form
7^0=36/8x=1
8x=36
x+36/8=9/2

RELATED QUESTIONS

log(2x + 3)=log... (answered by nerdybill)
Log base 7(2x-4)= log base... (answered by lynnlo)
log x + log (x2 - 16) - log 7 - log (x - 4) (answered by amarjeeth123)
Log 2x... (answered by MathLover1)
log(7-2x)=log(x+5) (answered by fractalier)
log(x+9)=log(2x-7) (answered by nerdybill)
log 10x - log (2x - 3) = log 7 solve for... (answered by stanbon)
log w = 7 log n = 4 (what is log... (answered by solver91311)
log x - log 7 =... (answered by Fombitz)