SOLUTION: (1/3)log(base4)*27-(2log(base4)*6-(1/2)log(base4)*81

Algebra.Com
Question 588476: (1/3)log(base4)*27-(2log(base4)*6-(1/2)log(base4)*81
Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
Evaluate:
(1/3)log(base4)*27-(2log(base4)*6-(1/2)log(base4)*81
(1/3)log4(27)-2log4(6)-(1/2)log4(81)
log4(27^1/3)-log4(6^2)-log4(81^1/2)
log4(3)-log4(36)-log4(9)
log4[3/36*9]
log4(1/108)
change to base 10 so you can use the calculator
log(1/108)/log4
≈-3.377

RELATED QUESTIONS

Solve: 2log(base4)x+log(base4)3=log(base4)x-log(base4)2 (answered by rapaljer)
Log base4 (x^2 - 3) + Lobg base4... (answered by Earlsdon)
Log(base4)(2x+1)=Log(base4)(x-3)+Log(base4)(x+5) (answered by Nate)
how do you write the expression as a single logarithum: 1/2[log(base4)(x+1) +... (answered by gonzo)
log(base4)(x-9)-log(base4)(x+3)=2 (answered by lwsshak3)
Simplify: 2log(base4)9 -... (answered by stanbon)
find the two values of x that satisfy the equation:... (answered by nerdybill,josmiceli)
Solve logxbase8 + log(1/6)base4 =... (answered by mathsolverplus,greenestamps)
log(base2)(log(base4)x)=1 (answered by Fombitz)