SOLUTION: log(base 9)(x-5)+log(base 9)(x+3)=1
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Question 588150: log(base 9)(x-5)+log(base 9)(x+3)=1
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
log(base 9)(x-5)+log(base 9)(x+3)=1
log9[(x-5)(x+3)]=1
9^1=(x-5)(x+3)
x^2-2x-15=9
x^2-2x-24=0
(x-6)(x+4)=0
x=6
or
x=-4 (reject, (x+3)>0)
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