SOLUTION: y=(sinx)^2(tanx)^4/(x^2+3)^2
again i can't figure it out. any help would be great
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Question 587797: y=(sinx)^2(tanx)^4/(x^2+3)^2
again i can't figure it out. any help would be great
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
y=(sinx)^2(tanx)^4/(x^2+3)^2
again i can't figure it out. any help would be great
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What do you want to do?
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y=(sinx)^2(tanx)^4*(x^2+3)^-2
Use the product rule:
y' =
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Sometimes you can combine and simplify
=
=
=
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