SOLUTION: please help me solve for x algebraically: log subscript 2 x + log subscript 2 (x+2) -log sub script 2 (4-x)=2

Question 587178: please help me solve for x algebraically:
log subscript 2 x + log subscript 2 (x+2) -log sub script 2 (4-x)=2
Found 2 solutions by nerdybill, lwsshak3:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
please help me solve for x algebraically:
log subscript 2 x + log subscript 2 (x+2) -log sub script 2 (4-x)=2
.

x = {-8, 2}
We throw out the negative solution (extraneous) leaving:
x = 2

Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
please help me solve for x algebraically:
log subscript 2 x + log subscript 2 (x+2) -log sub script 2 (4-x)=2
**
log2(x)+log2(x+2)-log2(4-x)=2
place under single log
log2[x(x+2)/(4-x)]=2
convert to exponential form: base(2) raised to log of number(2)=number[x(x+2)/(4-x)]
2^2=[x(x+2)/(4-x)]=4
(x^2+2x)=16-4x
x^2+6x-16=0
(x+8)(x-2)=0
x=-8 (reject, x>0)
or
x=2
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