SOLUTION: Please help me solve this equation: 2log(base4)x+3log(base8)x=10

Question 585733: Please help me solve this equation:
2log(base4)x+3log(base8)x=10
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Please help me solve this equation:
2log(base4)x+3log(base8)x=10
convert to log base2 using change of base formula: log(new base)(x)/log(new base)(old base)
2log2(x)/log2(4)+3log2(x)/log2(8)=10
log2(4)=2
log2(8)=3
2log2(x)/2+3log2(x)/3=10
LCD=6
6log2(x)+6log2(x)=60
12log2(x)=60
log2(x)=60/12=5
x=2^5=32

RELATED QUESTIONS
Please help me solve this. 2log (27/8) base x =6 and 1/3log x base 10... (answered by Theo)

Solve: 2 * log--base4 (x) + 3 * log--base8... (answered by lwsshak3)

combine 2log(base8)x - 2/3log(base8)x + 4log(base8) not sure how to combine with... (answered by ewatrrr)

Solve -2log(base8)(x + 1) =... (answered by lwsshak3)

can u help me solve this 3log(x-2) +... (answered by rapaljer)

Use properties of logarithms to solve the equation log(base4)(x+2)=... (answered by ewatrrr)

Please help me solve this:... (answered by nerdybill)

Solve: 2log(base4)x+log(base4)3=log(base4)x-log(base4)2 (answered by rapaljer)

Please help me solve this question Solve 4log underoot x base x�2 + 2log x sq base 4x... (answered by josgarithmetic)