SOLUTION: I am unable to solve this problem. Kindly help. Log10(x+y)/3 = 1/2(log10x + log10y) Now, prove that x/y + y/x = 7

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I am unable to solve this problem. Kindly help. Log10(x+y)/3 = 1/2(log10x + log10y) Now, prove that x/y + y/x = 7      Log On

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Question 5851: I am unable to solve this problem. Kindly help.
Log10(x+y)/3 = 1/2(log10x + log10y) Now, prove that x/y + y/x = 7
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
before anyone can help, you need to explain a couple of things:

1. is the 10 the base of the log?
2. the "/3" is this contained within the log ie log((x+y)/3) or outside, as in (log(x+y))/3. Your notation does not make it clear.

cheers
Jon.