SOLUTION: log(x-2)+log(x+2)-.5 log(x^2+4) how to rewrite this logarithm in single form?
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Question 584061: log(x-2)+log(x+2)-.5 log(x^2+4) how to rewrite this logarithm in single form?
Found 2 solutions by solver91311, josmiceli:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
A constant times a log is the log of the argument to the power of the constant, i.e. \ =\ n\log_b(x))
, so:
\ +\ \log(x\ +\ 2)\ -\ \log\left(\sqrt{x^2\ +\ 4}\right))
The sum of the logs is the log of the product, i.e.  + \log_b(y) = \log_b(xy))
, so:
(x\ +\ 2)\right)\ -\ \log\left(\sqrt{x^2\ +\ 4}\right))
\ -\ \log\left(\sqrt{x^2\ +\ 4}\right))
The difference of the logs is the log of the quotient, i.e.  - \log_b(y) = \log_b\left(\frac{x}{y}\right))
, so:
)
John
My calculator said it, I believe it, that settles it
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
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