SOLUTION: log(6)^x+log(6)^(x-9)=2 How do I solve for x? please help

Question 579298: log(6)^x+log(6)^(x-9)=2
How do I solve for x?
please help
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Your notation is confusing. I'll assume you meant log base 6:

x = {-3, 12}
But, since you can't take the log of a negative number, the -3 is an extraneous answer -- throw it out leaving:
x = 12
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