·64 = 1

Learn the rule:  "Flip the fraction, change the sign of the exponent":
That is,  becomes 

·64 = 1

becomes

·64 = 1

And we can dispense with the 1 denominator under the 16

   162v·64 = 1

Since 16 = 2·2·2·2 = 24 and since 64 = 2·2·2·2·2·2 = 26

(24)2v·26 = 1

Remove the parentheses by multiplying the exponent inside 4
by the exponent outside 2v, getting an exponent of 8v

28v·26 = 1

Add the exponents

28v+6 = 1

We know that 0 is the only exponent 2 can have to give 1,
since 20 = 1, so that means 8v+6 must equal 0.  So

8v + 6 = 0

    8v = -6

     v =  

Edwin